600 E Sanford St., Lake Alfred, FL 33850

600 E Sanford St., Lake Alfred, FL 33850
Photo 1 of 1
$320,000
Sold on 9/03/24
Beds Baths Sq. Ft. Taxes Built
3 2.00 1,559 $981 1975
On the market: 46 days
View full details, 15 photos, school info, and price history
The property you are inquiring about is located in Lake Alfred, FL in the East area of Polk County. This is just a gem in the easy-access area of Lake Alfred. Located on a corner lot of 100x141 with privacy fence, screened patio for entertaining around the pool. This beautiful 3 bedroom, 2 bathroom home, with open floorplan and durable tile throughout, nice fireplace in the gathering area, with new kitchen granite-topping, plus an additional flex room for lifestyle convenience, two-car garage, and a full-service house generator. Fabulous value in NO HOA! **Agents, please see MLS remarks.**
Listing courtesy of Renee Butler, BROKERS REALTY OF CENTRAL FLOR